计算:(1)=______;(2)=______;(3)=______;(4)(2b)3=______;(5)4y?(-2xy2)=______;(6)28x4y2÷

发布时间:2020-08-10 00:02:49

计算:
(1)=______;
(2)=______;
(3)=______;
(4)(2b)3=______;
(5)4y?(-2xy2)=______;
(6)28x4y2÷7x3y=______;
(7)(a+b)(a-b)=______.

网友回答

解:(1)==2;
(2)==3;
(3)==0.1;
(4)(2b)3=23?b3=8b3;
(5)4y?(-2xy2)=4×(-2)?x?(y?y2)=-8xy3;
(6)28x4y2÷7x3y=(28÷7)?(x4÷x3)?(y2÷y)=4xy;
(7)(a+b)(a-b)=a2-b2.
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