读入一正整数n(1<=n<=6)再读入n阶方阵a,计算该矩阵除副对角线，最后一列和最后一行以外的所有元素之和

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 #include <stdio.h>#define N 6int main(){int a[N][N],i,j,sum=0,n;printf("Input n:");scanf("%d",&n);printf("Input array:\n");for(i=0;i<n;i++)for(j=0;j<n;j++){printf("a[%d][%d]=",i,j);scanf("%d",&a[i][j]);}for(i=0;i<n;i++)for(j=0;j<n;j++)if(!(i+j==n-1||j==n-1||i==n-1))sum+=a[i][j];printf("sum=%d\n",sum);return 0;}